\(\int \csc (a+b x) \sin ^7(2 a+2 b x) \, dx\) [34]

Optimal result

Integrand size = 18, antiderivative size = 61 \[ \int \csc (a+b x) \sin ^7(2 a+2 b x) \, dx=\frac {128 \sin ^7(a+b x)}{7 b}-\frac {128 \sin ^9(a+b x)}{3 b}+\frac {384 \sin ^{11}(a+b x)}{11 b}-\frac {128 \sin ^{13}(a+b x)}{13 b} \]

[Out]

128/7*sin(b*x+a)^7/b-128/3*sin(b*x+a)^9/b+384/11*sin(b*x+a)^11/b-128/13*sin(b*x+a)^13/b

Rubi [A] (verified)

Time = 0.08 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {4373, 2644, 276} \[ \int \csc (a+b x) \sin ^7(2 a+2 b x) \, dx=-\frac {128 \sin ^{13}(a+b x)}{13 b}+\frac {384 \sin ^{11}(a+b x)}{11 b}-\frac {128 \sin ^9(a+b x)}{3 b}+\frac {128 \sin ^7(a+b x)}{7 b} \]

[In]

Int[Csc[a + b*x]*Sin[2*a + 2*b*x]^7,x]

[Out]

(128*Sin[a + b*x]^7)/(7*b) - (128*Sin[a + b*x]^9)/(3*b) + (384*Sin[a + b*x]^11)/(11*b) - (128*Sin[a + b*x]^13)
/(13*b)

Rule 276

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rule 2644

Int[cos[(e_.) + (f_.)*(x_)]^(n_.)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_.), x_Symbol] :> Dist[1/(a*f), Subst[Int[
x^m*(1 - x^2/a^2)^((n - 1)/2), x], x, a*Sin[e + f*x]], x] /; FreeQ[{a, e, f, m}, x] && IntegerQ[(n - 1)/2] &&
!(IntegerQ[(m - 1)/2] && LtQ[0, m, n])

Rule 4373

Int[((f_.)*sin[(a_.) + (b_.)*(x_)])^(n_.)*sin[(c_.) + (d_.)*(x_)]^(p_.), x_Symbol] :> Dist[2^p/f^p, Int[Cos[a
+ b*x]^p*(f*Sin[a + b*x])^(n + p), x], x] /; FreeQ[{a, b, c, d, f, n}, x] && EqQ[b*c - a*d, 0] && EqQ[d/b, 2]
&& IntegerQ[p]

Rubi steps \begin{align*} \text {integral}& = 128 \int \cos ^7(a+b x) \sin ^6(a+b x) \, dx \\ & = \frac {128 \text {Subst}\left (\int x^6 \left (1-x^2\right )^3 \, dx,x,\sin (a+b x)\right )}{b} \\ & = \frac {128 \text {Subst}\left (\int \left (x^6-3 x^8+3 x^{10}-x^{12}\right ) \, dx,x,\sin (a+b x)\right )}{b} \\ & = \frac {128 \sin ^7(a+b x)}{7 b}-\frac {128 \sin ^9(a+b x)}{3 b}+\frac {384 \sin ^{11}(a+b x)}{11 b}-\frac {128 \sin ^{13}(a+b x)}{13 b} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.04 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.00 \[ \int \csc (a+b x) \sin ^7(2 a+2 b x) \, dx=\frac {128 \sin ^7(a+b x)}{7 b}-\frac {128 \sin ^9(a+b x)}{3 b}+\frac {384 \sin ^{11}(a+b x)}{11 b}-\frac {128 \sin ^{13}(a+b x)}{13 b} \]

[In]

Integrate[Csc[a + b*x]*Sin[2*a + 2*b*x]^7,x]

[Out]

(128*Sin[a + b*x]^7)/(7*b) - (128*Sin[a + b*x]^9)/(3*b) + (384*Sin[a + b*x]^11)/(11*b) - (128*Sin[a + b*x]^13)
/(13*b)

Maple [A] (verified)

Time = 8.56 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.77

method	result	size
default	\(-\frac {128 \left (\frac {\sin \left (x b +a \right )^{13}}{13}-\frac {3 \sin \left (x b +a \right )^{11}}{11}+\frac {\sin \left (x b +a \right )^{9}}{3}-\frac {\sin \left (x b +a \right )^{7}}{7}\right )}{b}\)	\(47\)
risch	\(\frac {5 \sin \left (x b +a \right )}{8 b}-\frac {\sin \left (13 x b +13 a \right )}{416 b}-\frac {\sin \left (11 x b +11 a \right )}{352 b}+\frac {\sin \left (9 x b +9 a \right )}{48 b}+\frac {3 \sin \left (7 x b +7 a \right )}{112 b}-\frac {3 \sin \left (5 x b +5 a \right )}{32 b}-\frac {5 \sin \left (3 x b +3 a \right )}{32 b}\)	\(97\)

[In]

int(csc(b*x+a)*sin(2*b*x+2*a)^7,x,method=_RETURNVERBOSE)

[Out]

-128/b*(1/13*sin(b*x+a)^13-3/11*sin(b*x+a)^11+1/3*sin(b*x+a)^9-1/7*sin(b*x+a)^7)

Fricas [A] (verification not implemented)

none

Time = 0.25 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.20 \[ \int \csc (a+b x) \sin ^7(2 a+2 b x) \, dx=-\frac {128 \, {\left (231 \, \cos \left (b x + a\right )^{12} - 567 \, \cos \left (b x + a\right )^{10} + 371 \, \cos \left (b x + a\right )^{8} - 5 \, \cos \left (b x + a\right )^{6} - 6 \, \cos \left (b x + a\right )^{4} - 8 \, \cos \left (b x + a\right )^{2} - 16\right )} \sin \left (b x + a\right )}{3003 \, b} \]

[In]

integrate(csc(b*x+a)*sin(2*b*x+2*a)^7,x, algorithm="fricas")

[Out]

-128/3003*(231*cos(b*x + a)^12 - 567*cos(b*x + a)^10 + 371*cos(b*x + a)^8 - 5*cos(b*x + a)^6 - 6*cos(b*x + a)^
4 - 8*cos(b*x + a)^2 - 16)*sin(b*x + a)/b

Sympy [F(-1)]

Timed out. \[ \int \csc (a+b x) \sin ^7(2 a+2 b x) \, dx=\text {Timed out} \]

[In]

integrate(csc(b*x+a)*sin(2*b*x+2*a)**7,x)

[Out]

Timed out

Maxima [A] (verification not implemented)

none

Time = 0.24 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.31 \[ \int \csc (a+b x) \sin ^7(2 a+2 b x) \, dx=-\frac {231 \, \sin \left (13 \, b x + 13 \, a\right ) + 273 \, \sin \left (11 \, b x + 11 \, a\right ) - 2002 \, \sin \left (9 \, b x + 9 \, a\right ) - 2574 \, \sin \left (7 \, b x + 7 \, a\right ) + 9009 \, \sin \left (5 \, b x + 5 \, a\right ) + 15015 \, \sin \left (3 \, b x + 3 \, a\right ) - 60060 \, \sin \left (b x + a\right )}{96096 \, b} \]

[In]

integrate(csc(b*x+a)*sin(2*b*x+2*a)^7,x, algorithm="maxima")

[Out]

-1/96096*(231*sin(13*b*x + 13*a) + 273*sin(11*b*x + 11*a) - 2002*sin(9*b*x + 9*a) - 2574*sin(7*b*x + 7*a) + 90
09*sin(5*b*x + 5*a) + 15015*sin(3*b*x + 3*a) - 60060*sin(b*x + a))/b

Giac [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.75 \[ \int \csc (a+b x) \sin ^7(2 a+2 b x) \, dx=-\frac {128 \, {\left (231 \, \sin \left (b x + a\right )^{13} - 819 \, \sin \left (b x + a\right )^{11} + 1001 \, \sin \left (b x + a\right )^{9} - 429 \, \sin \left (b x + a\right )^{7}\right )}}{3003 \, b} \]

[In]

integrate(csc(b*x+a)*sin(2*b*x+2*a)^7,x, algorithm="giac")

[Out]

-128/3003*(231*sin(b*x + a)^13 - 819*sin(b*x + a)^11 + 1001*sin(b*x + a)^9 - 429*sin(b*x + a)^7)/b

Mupad [B] (verification not implemented)

Time = 19.97 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.74 \[ \int \csc (a+b x) \sin ^7(2 a+2 b x) \, dx=\frac {-\frac {128\,{\sin \left (a+b\,x\right )}^{13}}{13}+\frac {384\,{\sin \left (a+b\,x\right )}^{11}}{11}-\frac {128\,{\sin \left (a+b\,x\right )}^9}{3}+\frac {128\,{\sin \left (a+b\,x\right )}^7}{7}}{b} \]

[In]

int(sin(2*a + 2*b*x)^7/sin(a + b*x),x)

[Out]

((128*sin(a + b*x)^7)/7 - (128*sin(a + b*x)^9)/3 + (384*sin(a + b*x)^11)/11 - (128*sin(a + b*x)^13)/13)/b